$$ extIt is given that y= frac3a+22a-4 extand x= fraca+3a+8 \$$

$$ extExpress y ext in terms of x.$$

From making use of $x$ to fix for $a$, I discovered that $$a = frac8x-31-x$$

Then ns proceeded to instead of $a$ right into $y$. Ns did this double to for sure no mistakes space made, and also my last answer because that both was

$$frac22x-720x-10$$

There"s a problem, the exactly answer is $$frac7-22x10-20x$$

This provides me want to cry, more so since I confirm it twice and I was an extremely careful around my working out, right here it is:

$$frac2+ 3(frac8x-31-x) 2(frac8x-31-x) -4 $$

$$ ightarrow$$

$$frac(frac2(1-x) + 3(8x-3)1-x)(frac-4(1-x)+2(8x-3)1-x)$$

$$ ightarrow$$

$$frac2(1-x) + 3(8x-3)1-x * frac1-x-4(1-x)+2(8x-3)$$

$$ ightarrow$$

$$frac22x-71-x * frac1-x20x-10$$

The $(1-x)$"s publication out$$ ightarrow$$

$$frac22x-720x-10$$

Can someone please tell me regarding what i did incorrectly in the process? give thanks to you in advance!


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Meers E. ChahineMeers E. Chahine
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Your price is $$frac22x-720x-10$$

And the books "correct" answer is $$frac7-22x10-20x$$

Yes? an alert what happens as soon as you main point both the numerator and denominator in her answer through $-1$? You"re really welcome.

You are watching: Y in terms of x


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GuyGuy
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You got the exactly answer. Just multiply both numerator and denominator by -1

$$frac22x-720x-10 = frac-1-1 imes frac7-22x10-20x$$


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edited Sep 6 "17 in ~ 19:22
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Brad S.Brad S.
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