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You are watching: Write a balanced equation for the combustion of liquid ethanol in air.

This is an example of a combustion reaction. Come answer this you must an initial balance the equation.
The easiest means is to set up the reaction equation without any kind of coefficients:
C2H6O + O2 --> CO2 + HOH
Now start balancing, very first with carbon, then through hydrogen and last the oxygen.
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This is an example of a combustion reaction. To answer this you must very first balance the equation.
The easiest method is to set up the reaction equation without any coefficients:
C2H6O + O2 --> CO2 + HOH
Now begin balancing, first with carbon, then with hydrogen and also last the oxygen.
There are 2 carbons ~ above the left and 6 hydrogens so you include a coefficient that 2 in front of the CO2 and also a 3 in front of the water.
C2H6O + O2 --> 2 CO2 + 3 HOH
Now count the variety of oxygen on the product side and also you gain seven. One oxygen come from the ethanol so you require 6 an ext from oxygen. Add a coefficient of 3 in front of the oxygen on the reactant side and also your reaction is balanced.
C2H60 + 3 O2 --> 2 CO2 + 3 HOH
This reflects you that for every mole of ethanol, friend will acquire 3 mole of water. Therefore if you start with 0.51 mole of ethanol, girlfriend will create 3 x .51 or 1.53 mole of water.
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