Okay, this would certainly most likely seem a pretty basic doubt however I can not understand this point. I know that as soon as the existing is not flowing in the battery the voltage throughout the terminals is the emf of the battery however as soon as existing flows then we should take right into account the internal resistance.

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Now, my doubt is that, if we take into consideration only the external resistance, then the current must have actually been greater than it would certainly have actually remained in the absence of internal resistance. So, I want to understand the behavior of the instantaneous existing (simply when the switch is connected) in the case once inner resistance is there.

Does the present instantly have actually a value of $fracVR+r$ wright here V is the emf of the cell and R and also r are the outside and also inner resistance respectively? Or does the present initially have actually the worth $fracVR$ and also then it decreases (at a rate also fast for humans} and also reaches the value $fracVR+r$ at a steady state?

The reason I obtained the principle in the second interpretation is that I believed the potential difference across the external resistance simply when the switch is linked is the battery"s emf (I may be wrong), so the existing initially should be the potential difference divided by resistance.


Okay, this doubt concerned me from trying to settle this question in JEE Cutting edge 2019 Paper 1


The answer is given as A, B and C (it is a one or more than one alternative correct question) in the main answer crucial. (Which I think, is correct)

Now, the answer provided by many people is A and B only, which is likewise backed by many renowned coaching institutes in India.

Coming to choice C, what I did was that once switch $S_1$ is linked and stable state is reached the potential difference across P and Q is 4V and also there is also a cell of 10V in series in the opposite direction in that branch. So the resultant voltage across the 30 ohms resistance just at the instance of closing the switch $S_2$ is 6V so the existing simply at the moment of cshedding the switch is $frac630 = 0.2$.

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While others did this. They reinserted the capacitors with tantamount cells which offers a circuit indistinguishable to 2 4V cells with interior resistances 70 and also 130 respectively and then they offered the formula for the parallel combicountry of resistors and got a solution other than $0.2$ $(0.079)$.

If I put my approach in the conmessage of the others method, I did assume somepoint that instantaneously the present does not circulation with the branches of 130 ohms and 70 ohms resistance initially. OR in other words, I believed of not consisting of the inner resistance in my interpretation of instantaneous existing. The entirety thing boils dvery own to what I"ve asked in my main question.