What is the well balanced equation for the burning of pentene in oxygen to develop water and carbon dioxide?
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You are watching: Identify the correct balanced equation for the combustion of pentene (c5h10).


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Combustion is a kind of a chemical reactivity in which the reactants are oxygen and also (usually) a hydrocarbon. The reactants of a combustion reaction are usually water and carbon dioxide. 

The initially area to begin would certainly be to translate the word equation into a chemical equation. 

Thus, the burning of...


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Combustion is a type of a chemical reactivity in which the reactants are oxygen and (usually) a hydrocarbon. The reactants of a combustion reactivity are generally water and carbon dioxide. 

The initially place to start would be to interpret the word equation right into a chemical equation. 

Hence, the combustion of pentene in oxygen to create water and also carbon dioxide becomes:

C5H10 + O2 ---> H2O + CO2

The goal of balancing a chemical equation is to have the very same number of atoms of each facet on the reactant side as tright here are on the product side. At this time, tright here are 5 carbon atoms, 10 hydrogen atoms, and 2 oxygen atoms on the reactant side. On the product side, there are 2 hydrogen atoms, 3 oxygen atoms and 1 carbon atom. 

Coefficients are used to add more of the absent atoms. Hence, the final well balanced equation would be:

2C5H10 (g) + 15O2 (g) ---> 10CO2 (g) + 10H2O (g)


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