800 insects were weighed and resulting measurements are given in a box plot having mean 118, Q1 114 and Q3 126 with start point 105 and range 41. If the 80th percentile that the measurements is 130 mg, around how plenty of measurements are between 126 mg and 130 mg?a) 41 b)42 c) 43 d) 40answer is 40, however i am not getting how calculate?
Brent, uncovered the answer for the inquiry i inquiry earlier.it is necessary to remember the Q3 will be in ~ 75 percentile, therefore 126 is at 75th percentile. We have 5 percentile difference.5 percent the 800 will give us the number of measurements.5/100 * 800 = 40 :) including to this note of Yogasuhas we have to note the percentile divides a group into hundred. Therefore Q1= 25 Percentile , Q2= 50 percentile and Q3= 75 percentile. Also can settle the concern in this way as well. Since percentile is similar to percentage, therefore 80% the 800 is 640, therefore 640th measure is 130mg. Currently 75% is 126mg we know 75% of 800 = 600. Therefore 600th measure is 126mg. Variety of measurements between 640th and 600th are: 640-600 =40 measurements.   The interquartile range = (3rd quartile) - (1st quartile)

For an example, let"s use the boxplot that shows up at 3:40 in the above video. The 3rd quartile = 8The 1st quartile = 3So, the interquartile selection = 8 - 3 = 5

Likewise, in the boxplot that shows up at 6:15 in the video, we get: Interquartile variety = 6 - 2 = 4

Does the help?

Cheers,Brent

Hello Brent,Please correct me if i am wrong, If we have actually a even collection of number we uncover Q2 which will be the component of finding Q1 and also Q3. If collection is odd climate we find Q2 and exclude the from recognize Q1 and also Q3. Kind of. If we have actually a even variety of values, climate Q2 = the mean of the 2 middlemost numbers. So, Q2 is not component of the lesser and greater numbers.

Consider this set 1, 2, 3, 4, 5, 6, 7, 8In this case, Q2 = 4.5So, the lesser values are 1, 2, 3, 4, and also the better values space 5, 6, 7, 8This means Q1 = 2.5 and also Q3 = 6.5

Now think about this set 1, 2, 3, 4, 5, 6, 7, 8, 9In this case, Q2 = 5So, the lesser values room 1, 2, 3, 4, and also the greater values space 6, 7, 8, 9This way Q1 = 2.5 and also Q3 = 7.5

Does that help?

Cheers, Brent

### I don't recognize yogasuhas

kevin - September 26, 2019
i don't understand yogasuhas instance problem. He claimed in his first post "Q2 126" and also then in the next article "126 is at 75th percentile". I don't understand exactly how he knows 126 is in ~ the 75th percentile. Deserve to you please explain.

### Good catch, Kevin!

Good catch, Kevin!

I think yogasuha expected to say that Q3 (not Q2) is 126 I"ve edited yogasuha"s original comment.

You are watching: Eight hundred insects were weighed and the resulting measurements

By the way, here"s the original question: https://greprepclub.com/forum/eight-hundred-insects-were-weighed-and-the...

Cheers, Brent

### Hi Brent,

teitsuyagre - November 23, 2019
hi Brent,I constantly make a mistake for this kind of questions.https://greprepclub.com/forum/for-the-31-used-cars-sold-last-month-at-car-dealership-x-3265.html"For the 31 provided cars marketed last month at vehicle Dealership X, i m sorry of the following might be the mean price?"I did incorrectly by ascending the variety of cars sold from a high number come low. 6,7,8 and also 10 respectively. Then, I find the 16th that the card for the mean which ranks in 8, the price is between 7000\$-10,000\$.I am very confused now, or probably my equipment will correct if the inquiry asked "the median car"?

Even if girlfriend accidentally arrange the values from highest to lowest, the typical will still be the same.

We"re in search of the 16th value. So, if we arrange the values from greatest to lowest, the first 6 values are better than \$10,000. The next 8 worths are in between \$7500 and also \$10,000At this point we have actually accounted because that 14 numbers. To discover the 16th number, we"ll start adding the next set of values, i beg your pardon are between \$5000 and \$7499So, the 16th value (the median) will be in between \$5000 and \$7499

Does the help?

Cheers,Brent

### The weird no. Of worths which

Karenn
1355 - January 15, 2020
The odd no. Of worths which you explained at the 5.18min, execute you median if the complete no. The the set which is 11 (assume weird no.) or Q2 = 5?your reply is highly appreciated

### Whenever we have actually a collection with

Whenever we have actually a set with an ODD variety of values, then we don"t include the median amongst the lesser and also greater numbers.

Consider the following set of values: 2,2,3,4,7,8,8,10,11Here we have actually an odd variety of values. The mean = 7, so Q2 = 7The lesser numbers are: 2,2,3,4The typical of the lesser number is 2.5. Therefore Q1 = 2,5The higher numbers are: 8,8,10,11The typical of the better numbers is 9. So, Q3 = 9

Does the help?

### Dear brent,

Karenn
1355 - January 15, 2020
to ~ brent,I am a little confused should we to exclude, Q2 = typical from lesser no. And greater no. All the time or just when our set of no. Is odd?thanks

### We exclude, the median from

We exclude the mean from the lesser and also greater numbers ONLY once the set has one ODD variety of values.

When we have an EVEN number of values, the mean is the median of the 2 middlemost values. Due to the fact that the mean lies in between the two middlemost values, the typical divides the values right into two same sets.

Consider this set: 1,1,2,3,4,6,7,8,9,9In this instance we have an EVEN number of values (10 values). The mean of the 10 worths is 5. So, Q2 = 5Notice the the median divides the collection into two groups of five values. The lesser numbers room 1,1,2,3,4And the greater numbers are 6,7,8,9,9

Does the help?

### How did girlfriend come up v the

Juwam2010 - august 5, 2020
just how did you come up v the 800 worth in the section b component of this question? https://greprepclub.com/forum/eight-hundred-insects-were-weighed-and-the-resulting-measur-13743.html

The inquiry tells us that "Eight hundred insects to be weighed..."

Post your inquiry in the Comment section below, and also a GRE expert will answer the as quick as humanly possible.

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